CALCULATIONS
VDD=1.8V , L=0.36u , GAIN(A)=0.95
Rout=50 ohm, CL= 5pf
Using B.W =
2CLBW= 636.61MHz
Now , Gain (A) =
and Rout = 1/Gm||Ro||Rs
On solving both the equation , we get
Gm=19mS =1000 ohm
Now , let Gm/Id = 15.1 Id=1.26mA
Gm/Gds = 38.2 Gds=497uS Ro=2.012 K ohm
And hence , Rs=1.988 K ohm ( by further inspection taken as 720 ohm )
Vgs = 0.543V Vg = vgs + vs =1.443 V
Id/W=5.65 W=223u